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// A non-generic class can be the base class of a generic derived class using System; // A non-generic class class NonGen { int num; public NonGen(int i) { num = i; } public int GetNum() { return num; } } // A generic derived class class Gen<T> : NonGen { T ob; public Gen(T o, int i) : base (i) { ob = o; } // Return ob public T GetOb() { return ob; } } // Create a Gen object class HierDemo3 { static void Main() { // Create a Gen object for string Gen<String> w = new Gen<String>("Hello", 47); ConsoleWrite(wGetOb() + " "); ConsoleWriteLine(wGetNum()); } }

The free variable in this problem is time, so we differentiate equation ( ) with respect to time t It is important that we keep the Chain Rule in mind as we do so1 The result is dV 4 dr = 3r 2 dt 3 dt ( )

The output from the program is shown here:

Part I:

In the program, notice how Gen inherits NonGen in the following declaration:

class Gen<T> : NonGen {

Now we are given that dV /dt = 20 Our question is posed at the moment that V = 64 But, according to ( ) , this means that r = 3 48/ Substituting these values into equation ( ) yields 20 = Solving for dr/dt yields dr 5 = 2/3 dt 48 1/3 Thus the radius is increasing at the specified rate 4 3 3

Because NonGen is not generic, no type argument is specified Thus, even though Gen declares the type parameter T, it is not needed by (nor can it be used by) NonGen Thus, NonGen is inherited by Gen in the normal way No special conditions apply

A virtual method in a generic class can be overridden just like any other method For example, consider this program in which the virtual method GetOb( ) is overridden:

// Overriding a virtual method in a generic class using System; // A generic base class class Gen<T> { protected T ob; public Gen(T o) { ob = o; } // Return ob This method is virtual public virtual T GetOb() { ConsoleWrite("Gen s GetOb(): " ); return ob; } } // A derived class of Gen that overrides GetOb() class Gen2<T> : Gen<T> { public Gen2(T o) : base(o) { }

14 (7) 7

48/

// Override GetOb() public override T GetOb() { ConsoleWrite("Gen2 s GetOb(): "); return ob; } } // Demonstrate generic method override class OverrideDemo { static void Main() { // Create a Gen object for int Gen<int> iOb = new Gen<int>(88); // This calls Gen s version of GetOb() ConsoleWriteLine(iObGetOb());

18:

// Now, create a Gen2 object and assign its // reference to iOb (which is a Gen<int> variable) iOb = new Gen2<int>(99);

// This calls Gen2 s version of GetOb() ConsoleWriteLine(iObGetOb()); } }

A 13-foot ladder leans against a wall (Figure 315) The foot of the ladder begins to slide away from the wall at the rate of 1 foot per minute When the foot is 5 feet from the wall, at what rate is the top of the ladder falling

The output is shown here:

Gen s GetOb(): 88 Gen2 s GetOb(): 99

As the output confirms, the overridden version of GetOb( ) is called for an object of type Gen2, but the base class version is called for an object of type Gen Notice one other thing: This line

Let h( t) be the height of the ladder at time t and b( t) be the distance of the base of the ladder to the wall at time t Then the Pythagorean theorem tells us that h( t) 2 + b( t) 2 = 132 We may differentiate both sides of this equation with respect to the variable t (which is time in minutes) to obtain 2 h( t) h ( t) + 2 b( t) b ( t) = 0 Solving for h ( t) yields h ( t) = b( t) b ( t) h( t)

iOb = new Gen2<int>(99);