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If count is not null, then it contains a value The second way to determine if a nullable type contains a value is to use the HasValue read-only property defined by Nullable<T> It is shown here: bool HasValue HasValue will return true if the instance on which it is called contains a value It will return false otherwise Using the HasValue property, here is the second way to determine if the nullable object count has a value:

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Assuming that a nullable object contains a value, you can obtain its value by using the Value read-only property defined by Nullable<T>, which is shown here: T Value It returns the value of the nullable instance on which it is called If you try to obtain a value from a variable that is null, a SystemInvalidOperationException will be thrown It is also possible to obtain the value of a nullable instance by casting it into its underlying type The following program puts together the pieces and demonstrates the basic mechanism that handles a nullable type:

// Demonstrate a nullable type using System; class NullableDemo { static void Main() {

Consider the limit f (x) g (x)

Part I:

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What did you think of Harriet s E-mail Most people think it s pretty good It s bene t oriented and reader focused (scoring a seven on the Empathy Index) It has a good lead and the close suggests speci c action It adheres to the standards of excellence we ve discussed thus far What it lacks, however, is speci cs Review the paragraphs above the E-mail to remind yourself of the facts and numbers that are available, and revise Harriet s E-mail to add speci city How did you do Were you able to integrate several numbers into the text As you read your revision, can you hear how every sentence sounds stronger and more believable when numbers and statistics are included There are several effective ways to revise Harriet s E-mail Here s one:

int count = null; if(countHasValue) ConsoleWriteLine("count has this value: " + countValue); else ConsoleWriteLine("count has no value"); count = 100; if(countHasValue) ConsoleWriteLine("count has this value: " + countValue); else ConsoleWriteLine("count has no value"); } }

The output is shown here:

count has no value count has this value: 100

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If limx c f (x) exists and limx c g (x) exists and is not zero then the limit ( ) is straightforward to evaluate However, as we saw in Theorem 23, when limx c g (x) = 0 then the situation is more complicated (especially when limx c f (x) = 0 as well) For example, if f (x) = sin x and g (x) = x then the limit of the quotient as x 0 exists and equals 1 However if f (x) = x and g (x) = x 2 then the limit of the quotient as x 0 does not exist In this section we learn a rule for evaluating indeterminate forms of the type ( ) when either limx c f (x) = limx c g (x) = 0 or limx c f (x) = limx c g (x) = Such limits, or forms, are considered indeterminate because the limit of the quotient might actually exist and be finite or might not exist; one cannot analyze such a form by elementary means

A nullable object can be used in expressions that are valid for its underlying type Furthermore, it is possible to mix nullable objects and non-nullable objects within the same expression This works because of the predefined conversion that exists from the underlying type to the nullable type When non-nullable and nullable types are mixed in an operation, the outcome is a nullable value The following program illustrates the use of nullable types in expressions:

// Use nullable objects in expressions using System; class NullableDemo { static void Main() { int count = null; int result = null; int incr = 10; // notice that incr is a non-nullable type // result contains null, because count is null result = count + incr; if(resultHasValue) ConsoleWriteLine("result has this value: " + resultValue); else ConsoleWriteLine("result has no value"); // Now, count is given a value and result will contain a value count = 100; result = count + incr;

20:

Theorem 51 (l'H pital's Rule)

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